x^2-4=(x-2)(x+2)

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Solution for x^2-4=(x-2)(x+2) equation:


Simplifying
x2 + -4 = (x + -2)(x + 2)

Reorder the terms:
-4 + x2 = (x + -2)(x + 2)

Reorder the terms:
-4 + x2 = (-2 + x)(x + 2)

Reorder the terms:
-4 + x2 = (-2 + x)(2 + x)

Multiply (-2 + x) * (2 + x)
-4 + x2 = (-2(2 + x) + x(2 + x))
-4 + x2 = ((2 * -2 + x * -2) + x(2 + x))
-4 + x2 = ((-4 + -2x) + x(2 + x))
-4 + x2 = (-4 + -2x + (2 * x + x * x))
-4 + x2 = (-4 + -2x + (2x + x2))

Combine like terms: -2x + 2x = 0
-4 + x2 = (-4 + 0 + x2)
-4 + x2 = (-4 + x2)

Add '4' to each side of the equation.
-4 + 4 + x2 = -4 + 4 + x2

Combine like terms: -4 + 4 = 0
0 + x2 = -4 + 4 + x2
x2 = -4 + 4 + x2

Combine like terms: -4 + 4 = 0
x2 = 0 + x2
x2 = x2

Add '-1x2' to each side of the equation.
x2 + -1x2 = x2 + -1x2

Combine like terms: x2 + -1x2 = 0
0 = x2 + -1x2

Combine like terms: x2 + -1x2 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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